Engineering formula
Hertz Contact of Spherical Surfaces
$$a = (3FR* / 4E*)^(1/3)$$
For axisymmetric Hertz contact of two spherical surfaces, a normal force $F$ produces a circular contact area of radius $a$:
$$a=\left(\frac{3FR^*}{4E^*}\right)^{1/3}.$$
The maximum contact pressure is:
$$p_0=\frac{3F}{2\pi a^2}.$$
The pressure distribution is:
$$p(r)=p_0\sqrt{1-\frac{r^2}{a^2}},\qquad 0\le r\le a.$$
- $F$ — normal force;
- $a$ — contact radius;
- $R^*$ — reduced radius of curvature;
- $E^*$ — reduced elastic modulus;
- $p_0$ — maximum contact pressure;
- $p(r)$ — contact pressure at radial coordinate $r$;
- $r$ — radial coordinate within the circular contact patch.
The formulas apply within the assumptions of classical elastic Hertz theory.